Question

Differentiation of xy+y×y=tanx+y

Answer 1

Answer:

y'=(sec^2(x)-y)/(x+2y-1)

Step-by-step explanation:

=xy+y×y=tanx+y

=xy'+y+2yy'=sec^2(x)+y'

=y'=(sec^2(x)-y)/(x+2y-1)