Question

differentiation of y=1+x^2/1-x^2​

Answer 1

Step-by-step explanation:

$y = \frac{1 + {x}^{2} }{1 - {x}^{2} } \\ \frac{dy}{dx} = \frac{(1 - {x}^{2} )( 2x) - (1 + {x}^{2})(-2x) }{ {(1 - {x}^{2}) }^{2} } \\ \frac{dy}{dx} = \frac{ 2 x - 2 {x}^{3} +2x + 2 {x}^{3} }{ {(1 - {x}^{2} )}^{2} } \\ \frac{dy}{dx} = \frac{ 4x}{ {(1 - {x}^{2}) }^{2} }$

Answer 2

Answer:

ash k he do ha ki CV Gautam ha ha hai