differentiation of y=a cos x/3
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dy/dx = -a(sinx/3)/3
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Answer:
dy/dx = a(sin(x/3))/3.
Explanation:
On differentiating a constant we get the value as zero. So, in this case the differentiating is done on the basis of the chain rule theorem, Which states that the function is differentiated first then the variables inside it is also differentiated and multiplied.
Since, differentiating sinx we will get cosx and on differentiating x/3 we will get 1/3. So, on differentiating the a(cos(x/3)) we will apply chain rule and differentiate as u.v since a is constant hence the second term will be zero. So, on differentiating we will get a(sin(x/3))*1/3( here the 1/3 is the chain rule product). So, the final value is a(sin(x/3))/3.
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