Question

Differentiation of y = e^x * sin x * cos x​

Answer 1

$y=e^{x}*sinx*cosx$

$y = e^x * (cos x) * (-sinx)$

$y= -(e^x * sin x cos x)$

FORMULA USED:- [ ∵ e^x = e^x , sinx = cosx, cosx = -sinx]

Please mark as brainliest.

Thanku.