differentiation of Y is equal to e power of X + 3 log x
Answers
Answered by
0
ln x = logex.
y = ln x implies e y = x.
In other words, this logarithm function --
y = ln x
-- has for its inverse the exponential function,
y = ex.
Here are the inverse relations:
ln ex = x and eln x = x.
And the logarithm of the base itself is always 1:
ln e = 1.
y = ln x implies e y = x.
In other words, this logarithm function --
y = ln x
-- has for its inverse the exponential function,
y = ex.
Here are the inverse relations:
ln ex = x and eln x = x.
And the logarithm of the base itself is always 1:
ln e = 1.
Answered by
0
Helloo!!
see the attachment!!
see the attachment!!
Attachments:
Similar questions