Question

differentiation of y= logₐ(x) + logₐ(a) + logₓ(a)​

Answer 1

Answer:

1/x ln(a)

Step-by-step explanation:

y= logₐ(x) + logₐ(a) + logₓ(a)​

dy/dx = 1/x ln (a) + 0 + 0

=>dy/dx=1/x ln(a)

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