Differentiation of y = sec⁴x
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y = sec⁴x
we know , If any function y = {f(x)}^n given then,
differentiation of y, with respect to x
dy/dx = n.{ f(x)}^(n -1) .df(x)/dx
use this concept here,
y = ( secx)⁴
differentiate with respect to x
dy/dx = 4(secx)^(4-1).d(secx)/dx
=4.(secx)³.secx.tanx
=4(secx)⁴.tanx
=4sec⁴x.tanx
[ note :- differentiation of secx = secx.tanx]
we know , If any function y = {f(x)}^n given then,
differentiation of y, with respect to x
dy/dx = n.{ f(x)}^(n -1) .df(x)/dx
use this concept here,
y = ( secx)⁴
differentiate with respect to x
dy/dx = 4(secx)^(4-1).d(secx)/dx
=4.(secx)³.secx.tanx
=4(secx)⁴.tanx
=4sec⁴x.tanx
[ note :- differentiation of secx = secx.tanx]
Anonymous:
thanks a lot :)
Answered by
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Differentiation of y = sec⁴x
y = sec⁴x
dy/dx = 4 (secx)³ (secx tanx)
= 4sec⁴x.tanx
y = sec⁴x
dy/dx = 4 (secx)³ (secx tanx)
= 4sec⁴x.tanx
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