Question

differentiation of :-
y= sinx.cosx.​

Answer 1

thanks for question!!

refer to attachment!!

Answer 2

Answer:

cos2x

Step-by-step explanation:

y = sinx. cosx

it is in the form of u × v

so lets use

(uv)' = uv' + vu'

Here

u = sinx

v = cosx

y' = sinx .(cosx)' + cosx .( sinx)'

(sinx)' = cosx

(cosx)' = -sinx

y' = sinx. (-sinx ) + cosx. (cosx)

y' = - sin^2x + cos^2x

y' = cos^2x - sin^2x

y' = cos2x