Question

differentiation of y=√x+1/2√x

Answer 1

Answer:

3/(4√x)

Use the sum rule for the function.

ie. d(f+g)/dx = df/dx + dg/dx

Answer 2

Answer:

answer is -3/4$\sqrt[-3/2]{x}$

Explanation:

given y=$\sqrt{x}$+1/2$\sqrt{x}$

we can also write this as

y = $\sqrt{x}$/2$\sqrt{x}$   +1/2$\sqrt{x}$  both of them above the question are literally same

y=1/2+1\2$\sqrt{x}$ now diffrentiating on both side we get

dy/dx=0+1/2$\sqrt[-3/2]{x}$(-3/2)

dy/dx= --3/4$\sqrt[-3/2]{x}$