Question

differentiation
plz plz plz
sol this equation ​

Answer 1

Step-by-step explanation:Let y = Sin^-1 (1–2x^2)

Put x = sin θ.

Then y = sin^-1 (1–2 sin^2 θ)

= sin^-1 (cos 2θ)

= sin^-1 {sin (π/2 - 2θ)}

= π/2 - 2 θ

So y = π/2 -2 sin ^-1 x

Hence dy/dx = -2/{rt (1- x^2)}

Answer 2

Answer:

Hey mate plzz refer to the attachment