Differentiation
Q. y = sinx/x
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Answered by
4
Answer :
Given that, y = sinx/x ...(i)
Now, differentiating both sides of (i) with respect to x, we get
dy/dx = d/dx (sinx/x)
= {x d/dx (sinx) - sinx d/dx (x)}/(x^2)
= (x cosx - sinx)/(x^2)
We have used the formula -
d/dx (u/v)
= (v du/dv - u dv/du)/(v^2)
Hope it helps!
Given that, y = sinx/x ...(i)
Now, differentiating both sides of (i) with respect to x, we get
dy/dx = d/dx (sinx/x)
= {x d/dx (sinx) - sinx d/dx (x)}/(x^2)
= (x cosx - sinx)/(x^2)
We have used the formula -
d/dx (u/v)
= (v du/dv - u dv/du)/(v^2)
Hope it helps!
Answered by
2
Hey !!!
y = sinx / x
dy / dx = d (sinx/x ) /dx
=> Using divide rule of differentiation
dy/dx = x d( sinx )dx - sinx d ( x )/dx / x²
=> xcosx - sinx / x²
For better understanding , I provide you a attachment .
__________________________
Hope it helps you !!!
@Rajukumar111
y = sinx / x
dy / dx = d (sinx/x ) /dx
=> Using divide rule of differentiation
dy/dx = x d( sinx )dx - sinx d ( x )/dx / x²
=> xcosx - sinx / x²
For better understanding , I provide you a attachment .
__________________________
Hope it helps you !!!
@Rajukumar111
Attachments:
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