Question

differentiation
sin(ax+b)​

Answer 1

I think it would be helpful to you

Answer 2

let y = sin(ax+b)

using chain rule

dy/dx = (d(sin(ax+b))/dx)*(d(ax+b)/dx)

d(sin(x))/dx = cosx

d(ax+b) = a*(dx/dx) + 0 = a*1 = a

dy/dx = cos(ax+b)*a

hence derivative of sin(ax+b) = acos(ax+b)

:-)