Question

Differentiation wrt x


y= 1/cosecx + cotx

Answer 1

Answer:

dy/dx = 1/2 sec x/2

Step-by-step explanation:

Y='I/ cosecx + cot x

we know cosec x=1/sinx and cot x=cos x /sin x

we get ,

y.= sin x/ 1+cos x

y= 2sinx/2 cosx/2. / 2cos^x/2

y = tanx/2

now differentiate with respect to x

dy/dx =1/2sec ^x/2