Differentiation xy log(x+y)=1
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Differentiating w.r.t x
xy/(x+y)×(1+dy/dx)+xdy/dx×log(x+y)+ylog(x+y)=0
(xy+xy(dy/dx))/(x+y) + x(dy/dx)log(x+y) + ylog(x+y)=0
dy/dx(xy/(x+y) + xlog(x+y)=-(xy/(x+y) + ylog(x+y))
dy/dx=-(xy/(x+y) + ylog(x+y))/ (xy/(x+y) + xlog(x+y))
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