differentiation Y is equal to a x square + bx + c
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Answered by
1
Answer:
y=x^2+bx+c
So,dy/dx=2x+b+0
=2x+b
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Answered by
3
Using formula,
dx^n/dx = nx^(n-1)
And dc/dx =0
Here c is constant,
Applying formula in
Y= ax²+bx+c
→dy/dx = dax²/dx + dbx/dx +dc/dx
→dy/dx =a dx²/dx +b dx/dx +0
→ dy/dx =2ax +b (answer)
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