Differer
nation
of tanx÷√x
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Answer:
Explanation: let y = tanx÷ √x
= tanx ÷ x^1/2 = tanx × x^-1/2
So, differentiation of y
=Differentiation of tanx × x-1/2 + tanx × differentiation of x^-1/2 ( by product rule)
And, differentiation of tanx= sec^2x
And differentiation of x^-1/2 = x^-3/2
So, y' = sec^2x × x^-1/2 + tanx × x^-3/2.
Hope this helps
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