differntiate cos(ax+b)
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Answer:
-asin(ax+b)
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Let y =(ax + b) and z = sin(ax + b)
to formula, d(sinx)/dx=cosx
d(ax+b)/dx=d(ax)/dx+d(b)/dx
=a+0=a
According to chain rule of differentiation,
dz/dx=dz/dy×dy/dx
= cos(ax+b)×a
= acos(ax+b)
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