differntiate with respect to x: 1/√x+a-√x
Answers
Step-by-step explanation:
Here we are using the formula
differentiation of x^n is nx^(n-1)
differentiation of x^(1/2) is (1/2)x^(1/2-1)
(1/2)x^(-1/2)
(1/2)* 1/x^(1/2)
1/(2*x^(1/2))
differentiation of
or
x^(-1/2) is (-1/2)x^(-1/2-1)
(-1/2) * x^(-3/2)
(-1/2) * 1/(x^(3/2))
-1/(2*x^(3/2))
differentiation of constant is 0. so for a it is 0
The whole answer is
1/(2x^(1/2))-1/(2x^(3/2))
In this two terms common number is 1/2
so we take 1/2 as common number
(1/2)(1/x^(1/2)-1/x^(3/2))
Here we take LCM
(1/2) ( (x ^ (3/2)-x ^ (1/2)) / (x ^ (1/2+3/2) )
(1/2) ( (x ^ (3/2)-x ^ (1/2)) / (x ^ (4/2) )
(1/2) ( (x ^ (3/2)-x ^ (1/2)) / (x ^ 2) )
(1/2x^2)(x ^ (3/2)-x ^ (1/2))
Step-by-step explanation:
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