Question

differntiate with respect tox
d/dx(cos^2x)sin3x

Answer 1

$\frac{d( { \cos }^{2}x \sin3x) }{dx} \\ = \sin3x\frac{ d }{dx} { (\cos }^{2}x)+ { \cos }^{2}x \frac{d }{dx} ( \sin3x) \\ = \sin3x(2 \cos x ( - \sin x)) + { (\cos }^{2}x)(3 \cos 3x) \\ = - 2 \sin x\cos x\sin 3x + 3 \ { \cos}^{2}x \cos3x$