differntiate
x=acos^3Ф
y=bsin^3Ф
Arunav5:
it will be y= asin^3Ф
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Answered by
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dx/dФ=3acos^2Ф * (-sinФ)
now
dy/dФ=3bsin^2Ф * (cosФ)
so....................
dy/dx=-b/a * tanФ
now
dy/dФ=3bsin^2Ф * (cosФ)
so....................
dy/dx=-b/a * tanФ
Answered by
1
x=acos³Ф
therefore,dx/dФ=3acos²Ф(-sinФ)
likewise,dy/dФ=3bsin²Ф(cosФ)
Now,dy/dx=-b/a*tanФ
therefore,dx/dФ=3acos²Ф(-sinФ)
likewise,dy/dФ=3bsin²Ф(cosФ)
Now,dy/dx=-b/a*tanФ
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