Question

Differntiate y=tan x/ 1+cot x​

Answer 1

Answer:

Treat the tanx separately and the cotx separately. Don't forget the derivatives for trig functions:

enter image source here

Derivative of

tan

x

is

sec

2

x

. Derivative of

cot

x

is

−

csc

2

x

. Since they are adding together, we can treat them it as

tan

'

x

and

cot

'

(

x

)

:

f

'

(

x

)

=

sec

2

(

x

)

−

csc

2

(

x

)

Mark it as a brainlist ans Follow back

Answer 2

Answer:

based o the question: -->

we know that tan =1/ cot .

so , tan/ 1+cot.

[tan ( 1- cot)] / [(1+cot)(1-cot)]. { multiplying up and down with (1-cot)}.

(tan -1 ) / 1- cot square.

( we know that cot=1/tan so -tan cot is -1 and 1- cot square is cosec square. )

(tan-1)/ cosec square. ( we know that cosec square is also 1/ sin square. )

so, (tan-1)÷1/sin square as (tan-1)(sin square )

so, tan sin square -sin square ( we know that tan = sin / cos ).

so, [sin × sin square /cos ] / - sin square.

[sin cube - sin square ]/cos.

[sin square (sin -1)]/cos .

tanx sinx (sinx-1).

HOPES ITS HELP U MARK IT AS A BRAINLIST ANSWER . FOLLOW ME . RATE THIS ANSWER .