Question

differntiate ; y=(xcosx)^x
plz answer it now!

Answer 1

Step-by-step explanation:

y= (x.cos x)^x

lny =x ln(x.cosx)

1/y. dy/dx=ln(x.cosx) + x(1/x.cosx)(1-xsinx)

1/y.dy/dx = ln(x.cosx )+(1-xsinx)

dy/dx = {ln(x.cosx)+ (1-x.sinx).(x.cosx)^x