Differntiation of x^(n-1)
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Superman : " Don't Scare Miss , you have company "
d\dx (x^(n-1) ) = (n-1)[x^(n-2)]
#SupermanINFINITY
formula used : diff. of x^n = n(x^(n-1))
Superman : " Don't Scare Miss , you have company "
d\dx (x^(n-1) ) = (n-1)[x^(n-2)]
#SupermanINFINITY
formula used : diff. of x^n = n(x^(n-1))
SpinelessBabe:
perfect
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sorry miss
but im here to help
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**Superman wins** Haha, you're a great user and a great answerer! ✌
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hi friend here is the required answer
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