Question

differtiant with recpect to x​

Answer 1

Step-by-step explanation:

log(x+y) =log (xy)+a

d log (x+y)/dx=d log (xy)/dx +d a/dx

1/(x+y) d x/dx+dy/dx=1/xy xdy/dx +y dx/dx +0

1/x+y dy/dx =1/xy xdy/dx+y

1/x+y dy/dx -1/xy xdy/dx =y

dy/dx [1/x+y- /y]=y

dy/dx [-x/(x+y) y]=y

dy/dx=y [(x+y) y/-x]