Math, asked by shweta016, 1 year ago

differtiant with recpect to x​

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Answered by Anonymous
10

log(x + y) = logxy + a

log(1/y + 1/x) = a

1/y + 1/x = e^a

diffrenciating with Respect to x we get

-1/y^2 dy/dx - 1/x^2 = 0

dy/dx = - y^2/x^2

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