Diffetence isb14 lcm and hcf ate441 and 7 find the numbers
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Answer: 49 and 63
Step-by-step explanation:
Lat the numbers be X and Y
HCF × LCM = Product of the 2 numbers
441 × 7 = XY .......1
X-Y = 14
X = 14+Y. .......2
Put value of X from 2 in 1...
441×7 = Y(Y+14)
3087=Y^2 + 14Y
So, Y^2 + 14Y - 3087 = 0
= Y^2 + 63Y - 49Y - 3087 = 0
= Y(Y+63) - 49(Y+63) = 0
= (Y+63)(Y-49) = 0
So Y = -63 or 49
As Y can't be in Negetive
Y = 49
As X = Y+14
X = 49+14 = 63
So the 2 numbers are 49 and 63
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