Question

diffirencate y=sin x^x,

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Answer 1

Step-by-step explanation:

y = ( sin x)^ x

taking log on both the sides.

we get ,

log y = log ( sin x ) ^ x

Diff . w. r. t. x.

we get,

1 / y . dy/ dx = x .1 / sin x ( cos x ) + log ( sin x)

dy / dx = y [ x . cos x / sin x + log ( sin x)]

dy / dx = y [ x cot x + log ( sin x ).

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