Question

Diffraction Phenomena is observed using a double slit
illuminated light of 1 = 500 om . The srit width e-O'Olmm
be spacing between the two slits 'bro somm. The distance
of the screen from the slits is toom. Calculate the
distance b/w 1) central maxima & the 1st minimum of
the fringe envelop.2) every two consecutive double
slit dank fringe​

Answer 1

Answer:

When slit are of equal width, if I

o

is intensity of light then,

I

max

=I

o

+I

o

+2

I

o

I

o

=4I

o

I

min

=I

o

+I

o

−2

I

o

I

o

=0

Case 2: When slit are of unequal width, intensity from one slit would increase to twice then,

I

newmax

=2I

o

+I

o

+2

2I

o

I

o

=5.83I

o

I

newmin

=2I

o

+I

o

−2

2I

o

I

o

=0.17I

o

Therefore, intensities of both the maxima and the minima increase

Please mark me as brainliest and please follow me and thank my answers please