diffrence between two numbers is 30 .twice the greater number is less than 7 times the smaller number by 5 .find the number
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Answer:
let the numbers be p and q
p-q=30
2p-7q=5
Multiply first eqn by 2 and subtract from second eqn
2p-7q-(2p-2q)=5-60
-5q=-55
q=11
p=11+30=41
So the numbers are 41 and 11
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