Question

diffrence of any two sides of a triangle is greater then the third sides ​

Answer 1

Step-by-step explanation:

∠1>∠4 because Exterior angle is always greater than respective interior angle. Similarly, ∠2>∠3. Therefore ∠1>∠3 and BC>DC as size opposite to greater angle are also greater in length. Hence it is proved that either side of triangle is always greater than difference of remaining two sides.

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Answer 2

Answer:

$two \: sides \:of \: triangle \\ \: is \: greater \: than \: 3rd \: side$