Question

diffrentiate cot square x​

Answer 1

$\frac{d}{dx} {(cot}^{2} x) \\ \\ = 2(cotx)( - {cosec}^{2} x) \\ \\ = - 2cotx \: {cosec}^{2} x$

hope it helps.

Answer 2

$\large{ \bold{ \frac{d}{dx} ( {x}^{n} ) = n {x}^{n - 1} }} \\ \\ \large{ \bold{ \frac{d}{dx} (cotx) = - {cosec}^{2} x}} \\ \\ \large{ \bold{ \frac{d}{dx} ({cot}^{2} x) = 2cotx( - {cosec}^{2} x)}} \\ \\ = \large{ \bold{ - 2cotx \: {cosec}^{2} x}}$

hope it helps.