Math, asked by ronak7456, 7 months ago

Diffrentiate secx.Tanx.logx

Answers

Answered by salonibadge31

Step-by-step explanation:

The d/dx of log(secx+tanx) is sec x. we have to find the d/dx of given expression. Cancel out the common factor. Therefore the d/dx of log(secx+tanx) is sec x.

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