Difrence b/w two nubers is 4.and their product is 17.then find the sum of their squers?
Answers
Answered by
0
let numbers be a and b.
given, a-b=4
given, ab=17
(a-b)^2=a^2 + b^2 - 2ab
substituting, we get: 16=a^2+b^2-34
a^2+b^2=16+34=50
thus,answer=50.
Similar questions