Question

digit at one place of a two digit number is four time the digit at tens place.if number obtained by reversing the digit exceed by 54.find the number​

Answer 1

Answer:

number is 28

Reversed number is 82

Step-by-step explanation:

Let tens digit be x= 10x

One's digit be Y = y

Orignal Equation is: 10x+y

Reverse equation is: 10y+x

Y is four times of tens place= 4x

So our 1st equation is : y = 4x

Orignal number will exceed by reversing the digits by 54

Well Reversed number of 10x+y is 10y+x and we will get this equation

10x+y+54 = 10y+x

10x-x+y-10y= -54

9x -9y= -54

9(x-y)= -54

X-y = -54/9

X-y= -6

Now we get Equation 2 which is x-y = -6

and we know that y = 4x

So put the y value in equation 2

x-4x = -6

-3x = -6

x = -6/-3

x = 2

Now Put the x value in Equation one

Which is y= 4x

y = 4(2)

y = 8

Hence

Tens digit which is x = 2

And one's digit which is y= 8

Put these x and y values in orignal equation

Orignal number: 10x+y

10(2)+8= 28

Well the orignal number is 28

Now we will put x and y values in reverse equation

10y+x

10(8)+2= 82

So

orignal number is = 28

and reverse number is= 82

Hope its clear

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