Question

digit in the tenth place of a two digit number is 4 times 8 digit in the ones place if the digits are reversed the new number is 27 less than the original number find the original number and check the solution​

Answer 1

Answer:

41

Step-by-step explanation:

10x+y = 10y+x + 27

x = 4y

solve to find y = 1, x = 4

so number is 41