Question

____ digit is at one's place in cube of 17.​

Answer 1

Answer:

3 comes at the one's place of cube of 17

Step-by-step explanation:

7*7*7=313

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Answer 2

Question :- Digit is at one's place in cube of 17 ?

Solution :-

we know that, concept for unit digit of a cube number :-

→ 1³ = 1 = unit digit 1 .

→ 2³ = 8 = unit digit 8.

→ 3³ = 27 = unit digit 7.

→ 4³ = 64 = unit digit 4.

→ 5³ = 125 = unit digit 5.

→ 6³ = 216 = unit digit 6 .

→ 7³ = 343 = unit digit 3.

→ 8³ = 512 = unit digit 2.

→ 9³ = 729 = unit digit 9.

→ 10³ = 1000 = unit digit 0.

So, unit digit of a natural number depends on the unit digit of cube of one's place . As we can see none is repeating .

therefore,

(17)³ = unit place 7³ = 343 => 3 in last .

Hence, digit is at one's place in cube of 17 will be 3.

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Find the least number which when divide by 626, 618 and 676 leaves a remainder 3 in each

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