digits of two digit differ bythe digits of two digit differ by 3 if the digits are interchanged and the resulting number is added to the original number we get 121 find the original number
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Answer:
74
Step-by-step explanation:
Let x be the number at tens place.
And y be the number at unit place.
So the original number = 10x+y - - - - - (a)
Now, according to the ques,
x-y =3
=> x= 3+y - - - - - - - - (1)
When the digits are interchanged, the number becomes 10y+x
So,
10y+x + 10x+y = 121
=> 11x + 11y = 121
=> 11(3+y) +11y =121 [from (1)]
=> 33 + 11y + 11y= 121
=> 22y = 121-33
=> 22y = 88
=> y = 88/22
=> y= 4
Substituting this in eq (1),
x= 3+y
=> x= 3+4
=> x= 7
So, x=7 and y=4
In eq (a),
The original number = 10x +y
= 10(7) +4
= 70 +4
= 74
So, the original number was 74.
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