Digonals AC nad BD of a trapezium ABCD with AB||DC Intersect each other at the point O. Using a similarity criterion for two triangles, show that OA/OC= OB/OD.
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Answer:
ABCD is a trapezium with AB∥CD and diagonals AB and CD intersecting at O.
⇒ In △OAB and △OCD
⇒ ∠AOB=∠DOC [ Vertically opposite angles ]
⇒ ∠ABO=∠CDO [ Alternate angles ]
⇒ ∠BAO=∠OCD [ Alternate angles ]
∴ △OAB∼△OCD [ AAA similarity ]
We know that if triangles are similar, their corresponding sides are in proportion.
⇒
OC = OD
OA. OB
[henceproved]
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