Science, asked by sudheeshelk, 6 hours ago

dihybrid cross section between with 1. purple pea plant with green pod colour 2.white pea plant with yellow seed colour? with respective phenotype and genotype table and ratio?​

Answers

Answered by anjalirehan04
2

9 : 3 : 3 : 1

A cross is made between homozygous yellow round seeds(YYRR) to another homozygous green wrinkled seeds(yyrr). In the F1 generation, all plants are heterozygous yellow round(YyrRr). When this plant is subjected to self pollination, in the F2 generation, 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is green wrinkled are formed.

The dihybrid phenotypic ratio is 9:3:3:1.

If the heterozygous yellow seeds Yy are crossed with heterozygous yellow seeds Yy,

Parents: Yy x Yy

Gametes: Y, y x Y, y

Offspring: YY, Yy, Yy and yy

YY (yellow), Yy (yellow), Yy (yellow) and yy (green)

From the Punnett square, the phenotypic ratio is 3 (yellow): 1 (green).

The genotypic ratio is 1: 2: 1 (YY- 1, Yy-2 and yy-1).

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Answered by DakshRaj1234
1

Answer:

9:3:3:1

A cross is made between homozygous yellow round seeds(YYRR) to another homozygous green wrinkled seeds(yyrr). In the F1 generation, all plants are heterozygous yellow round(YyrRr). When this plant is subjected to self pollination, in the F2 generation, 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is wrinkled are formed. green

The dihybrid phenotypic ratio is 9:3:3:1.

If the heterozygous yellow seeds Yy are crossed with heterozygous yellow seeds Yy,

Parents: Yy x Yy

Gametes: Y, y x Y, y

Offspring: YY, Yy, Yy and yy YY (yellow), Yy (yellow), Yy (yellow) and yy (green)

From the Punnett square, the phenotypic ratio is 3 (yellow): 1 (green).

The genotypic ratio is 1: 2: 1 (YY- 1, Yy-2 and yy-1).

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