Biology, asked by nravinderraju, 9 months ago

Dihybrid test cross ratio with 90%
parental type and 10% recombinant typ
shows that genes have
UNS10110
CH
Flim
muhimin
WATUITO
UNUI
CIOLI
HUILE
TASDIE
SIL
FURTUE
TURLU
SUESISTER
the.
(A) Incomplete linkage
Unh
ME
20
EUR
TEEN
(B) Complete linkage
(C) Independent assortment
(D) No linkagea cross between a plant heterozygous for two factors and a plant necessary for both the factors give a phenotypic ratio of ​

Answers

Answered by tiwariakdi
0

(A) Incomplete linkage

  • The dihybrid test cross is a superior, simpler cross to test for independent assortment than the F1 x F1 cross, which yields a ratio of 9:3:3:1. Independent assortment in a dihybrid test cross is perceived as a ratio of 1:1:1:1, which is simpler to score than the 9:3:3:1 ratio. Additionally, it will be simpler to utilise this test cross to check for linkage.
  • Similar to monohybrid crosses, you can use dihybrid test crosses to identify the genotype of a person with dominant characteristics and see if they are homozygous dominant or heterozygous dominant. An individual with an unknown genotype in two loci is crossed to an individual who is homozygous recessive for both loci in this sort of cross.

Now, according to the given information, we are given that,

Dihybrid test cross ratio with 90% parental type and 10% recombinant type.

Now linking genes that display some cross-over or are intermediate in their effects between independent assortment and total linkage is called the incomplete linkage.

Hence, this is an example of an incomplete linkage.

Learn more here

https://brainly.in/question/1179023

#SPJ1

Similar questions