DIKETAHUI BALOK ABCD,EFGH DENGAN AB = [x+1] cm, BC = x cm, dan AC = [x+2] cm. jika tinggi balok 2 cm, volume balok adalah
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AC² = AB² + BC²
= (x+1)² + x²
x + 2 = 2x² + 2x + 1
2x²² + x - 1 = 0
(2x - 1)(x + 1) = 0
x = 1/2 atau x = -1 (tak memenehi, masa panjangnya negatif)
Panjang AB = x + 1 = 1/2 + 1 = 3/2 cm
BC = x = 1/2
CG = 2
Vol balok = AB(BC)(CG) cm³
= (3/2)(1/2)(2) cm³
= 3/2 Cm³
= (x+1)² + x²
x + 2 = 2x² + 2x + 1
2x²² + x - 1 = 0
(2x - 1)(x + 1) = 0
x = 1/2 atau x = -1 (tak memenehi, masa panjangnya negatif)
Panjang AB = x + 1 = 1/2 + 1 = 3/2 cm
BC = x = 1/2
CG = 2
Vol balok = AB(BC)(CG) cm³
= (3/2)(1/2)(2) cm³
= 3/2 Cm³
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