Question

Diksha has 20% lower chocolates than Riya, while Riya has 15% lower chocolates than Ankita. By how much percent is Ankita's chocolates are more than Diksha's chocolates?

Answer 1

Given,

Diksha has 20% lower chocolates than Riya.

Riya has 15% lower chocolates than Ankita.

To find,

The percentage by which Ankita's chocolates are more than Diksha's chocolates.

Solution,

We can simply solve this mathematical problem using the following process:

Let us assume that Ankita has x chocolates.

Now, according to the question;

Riya has 15% lower chocolates than Ankita

=> Riya has (100-15)% of chocolates that Ankita has

=> Riya has 85% of the chocolates that Ankita has

{Statement-1}

So, according to statement-1;

Number of chocolates with Riya

= 85% of chocolates that Ankita has

= 85% of x

= (85/100)×x

= 17x/20

Similarly, according to the question;

Diksha has 20% lower chocolates than Riya

=> Diksha has (100-20)% of chocolates that Riya has

=> Diksha has 80% of the chocolates that Riya has

{Statement-2}

So, according to statement-2;

Number of chocolates with Diksha

= 80% of chocolates that Riya has

= 80% of (17x/20)

= (80/100)×(17x/20)

= 17x/25

Now, according to the question;

Number of chocolates more with Ankita than Diksha

= (number of chocolates with Ankita) - (number of chocolates with Diksha)

= (x-17x/25)

= (25x-17x)/25

= 8x/25

Now, the percentage by which Ankita's chocolates are more than Diksha's chocolates

= (number of chocolates more with Ankita than Diksha)/(number of chocolates with Diksha) × 100

= (8x/25)/(17x/25) × 100

=(8/17)×100

= 47% (approx)

Hence, Ankita's chocolates are more than Diksha's chocolates by approximately 47%.

Answer 2

Answer:

Step-by-step explanation: