Question

Dil Cuso4 overall reaction​

Answer 1

Explanation:

Electrolyte CuSO4 dissociates as Cu2+ and SO42− along with H+ and OH− ions in the aqueous solution. 

At cathode (reduction):

As Cu2+ has higher reduction potential than H+, it gets preferentially reduced.

2Cu2++4e−→2Cu

At anode (oxidation):

As OH− has higher oxidation potential than SO42−, it gets preferentially oxidised.

4OH−→2H2O+O2+4e−

Hence, Cu at cathode and O2 at anode are produced by electrolysis of aqueous CuSO4 with inert electrodes.

Answer 2

Answer:

Electrolyte CuSO

4

dissociates as Cu

2+

and SO

4

2−

along with H+ and OH

−

ions in the aqueous solution.

At cathode (reduction):

As Cu

2+

has higher reduction potential than H

+

, it gets preferentially reduced.

2Cu

2+

+4e

−

→2Cu

At anode (oxidation):

As OH

−

has higher oxidation potential than SO

4

2−

, it gets preferentially oxidised.

4OH

−

→2H

2

O+O

2

+4e

−

Hence, Cu at cathode and O

2

at anode are produced by electrolysis of aqueous CuSO

4

with inert electrodes.