Math, asked by sumeshmanikandan, 1 year ago

Dilip buys a radio at 3/4 of its value and sells it for 20% more than its value. What is his gain? ​

Answers

Answered by OJASVI22
45

Answer:

Step-by-step explanation:

Let original price be "X".  

Buying price = 3X/4 = 0.75X  

Selling price = 20% more than X = X+20% of X = 1.2X  

Gain = 1.2X - 0.75X = 0.45X  

Percentage of Gain = (Gain/Buying price) * 100 = 60%.  

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Answered by ChitranjanMahajan
7

Given:

Dilip buys a radio at 3/4 of its value and sells it for 20% more than its value.

To Find:

The profit Dilip made

Solution:

Let original price of the radio be "x"

Buying price of Radio = \frac{3}{4}x = 0.75x

Selling price of Radio = 20% more than X = x + 20% of x = 1.2x

Profit = 1.2x - 0.75x = 0.45x

Percentage of Profit = \frac{Profit}{Buying price} × 100 = \frac{0.45x}{0.75x}×100 = 60%.

Hence, Dilip made a gain of 60%.

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