Question

Dilute aqueous solution of potassium fluoride is electrolysed the products at the anode and cathode are (a) o2 and k (b)o2 and F2 (C)H2 AND F2 (d) o2 and h2

Answer 1

$\underline\mathfrak{ANSWER:-}$

Ion with higher potential will go to corresponding electrode and discharge.

So,

NaF:

Cathode : 2H⊕+2e−→H2

Anode : 4O⊖H→O2+2H2O+4e−99

∴$\uparrow$ O2and H2