Physics, asked by swapnalikulkarni2063, 7 months ago

Dimantional correct check s=v+1/2at^2​

Answers

Answered by rohitkhajuria90
1

Explanation:

Dimensional check for correctness of equation

s = v +  \frac{1}{2} a {t}^{2}  \\ now \\ [s]  = [v]  + [a {t}^{2}  ]  \\ [ {M}^{o}  {L}^{1}  {T}^{o} ]  = [ {M}^{o}  {L}^{1}  {T}^{ - 1} ] = [ {M}^{o}  {L}^{1}  {T}^{ - 2} ][ {M}^{o}  {L}^{0}  {T}^{2} ] \\ {M}^{o}  {L}^{1}  {T}^{o} ]  = [ {M}^{o}  {L}^{1}  {T}^{ - 1} ] = [ {M}^{o}  {L}^{1}  {T}^{ o} ]

Dimension for s and at^2 are correct but for v is not. Hence the equation is not correct

the \: equation \\ s = vt +  \frac{1}{2} a {t}^{2} \\ is \: dimensionally \: correct

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