Question

dimension formula for intensity of magnification is

Answer 1

 M = Magnetic moment/volume = μM / V                            …1

Let       a = Uniform area of cross-section of the magnetised specimen.

           l = magnetic length of the specimen.

           m = strength of each pole of the specimen,

As                    μm = ml

and                   V = al

then equation (1) becomes

           M = m x 2l / a x 2l

or         M = m/a

thus intensity of magnetisation of  a  magnetic material is also defined as the pole strength per unit area of cross-section of the material.

Unit :    M= magnetic moment / Volume

           M= Amp.metre2 / metre3 = Am -1

These are S.I unit of M

Answer 2

The dimensional formula for intensity of magnification or magnification is $\[[{M^0}{L^0}{T^0}]\]$.

Explanation:

• Magnification is defined as the ratio of the height of the image and the height of the object.
• It is represented by the formula:

        $\[m = \frac{{Height\,of\,image}}{{Height\,of\,object}} = \frac{{h'}}{h}\]$

• The dimensional formula of any physical quantity is an expression that represents the base quantities included in it.
• It is represented by the symbols of the base quantities enclosed in square brackets.
• The base quantities included in the dimensional formula are mass which is represented by $M$, length represented by $L$ and time represented by $T$.
• For example, the dimensional formula for velocity is $\[[{M^0}L{T^{ - 1}}]\]$ as the unit of velocity is $\[m/s\]$.
• Therefore, to write the dimensional formula for magnification, we need to determine the unit of magnification.
• The formula of magnification is $\[m = \frac{{h'}}{h}\]$ and both numerator and denominator in the formula are heights which are represented in $cm$ or as length.
• Therefore, magnification has no units.
• Thus, the dimensional formula for magnification can be represented as $\[[{M^0}{L^0}{T^0}]\]$.

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