Question

Dimension formula of 1/2e0E^2

Answer 1

Answer: $ML^{-1}T^{-2}$

Explanation:

Given that,

Energy density is

$u = \dfrac{1}{2}\epsilon_{0}E^{2}$

We know that,

Energy density = Energy/volume

The energy density is the amount of energy per unit volume.

Energy = force X distance

Now, the dimension formula of energy

$E = MLT^{-2}\times L$

$E = ML^{2}T^{-2}$

Now, the dimension formula of energy density is

Energy density = Energy /volume

$u = \dfrac{ML^{2}T^{-2}}{L^{3}}$

$u = ML^{-1}T^{-2}$

Hence, this is the required solution.