Question

dimension
Numerical
A Gold biscuit of 6 cm x 4cmx0.1cm
placed on a table if density of
gold of 19600, calculate the maxim
and minimum pressure on table.
g =10 n/kg​

Answer 1

Explanation:

Measuring a quantity:

When a length is measured as 7 feets it means 7 times the length or a foot. What is measured (i.e. the quantity) consist of a number (7) multiplied by the chosen unit (foot, metre, etc.).

 

Fundamental and derived quantities:

Several quantities, like mass, length, time, temperature, are called fundamental or base quantities, while other are derived from these. One example is a velocity which is a length divided by a time.

 

Answer 2

The maximum pressure is 1.175 x 10⁴ N/m²

The minimum pressure is 196 N/m²

Explanation:

Dimensions of the biscuit = 6 cm x 4 cm x 0.1 cm

Minimum area of one surface of the gold biscuit = 4 x 0.1 = 0.4 cm²

Maximum area of one surface of gold biscuit = 6 x 4 = 24 cm²

Volume of the gold biscuit = 6 x 4 x 0.1 cm³

                                            = 2.4 cm³

                                            = 2.4 x 10⁻⁶ m³

We know that

Mass = Volume x Density

Given density of the gold = 19600 kg/m³

Thus,

mass of gold biscuit = 2.4 x 10⁻⁶ x 19600 = 0.047 kg

We know that

Pressure = Force/Area

Thus, when the contact area is minimum, the pressure will be maximum and vice versa

Here the force will be the force acting on the body due to gravity

F = 0.047 x 10 N = 0.47 N

Thus,

Maximum pressure = 0.47/(0.4 x 10⁻⁴) = 1.175 x 10⁴ N/m²

Minimum pressure = 0.47/(24 x 10⁻⁴) = 0.0196 x 10⁴ N/m² = 196 N/m²

Hope this answer is helpful.

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