Dimension of electric field
Answers
Answer:
The SI unit of electric field strength is newtons per coulomb (N/C) or volts per meter (V/m). The force experienced by a very small test charge q placed in a field E in a vacuum is given by E = F/q, where F is the force experienced. =M^1.L^1. T^(-3).
Explanation:
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Answer:
The dimensional formula for electric field is
Explanation:
Force on a point charge is given by Coulomb’s Law. Coulomb’s Law gives magnitude of force(F) between two point charges q1 and q2 separate by distance r.
Where,
Here, Unit of force = Newton & unit of
Electric field (E) is field produced by a charge Q around its surroundings.
Say a point test charge q is placed at distance r from Q. Then --- (2)
From (1) & (2), we can observe that,
E = F/q = m x a / I x t
= Newton / Coulomb = Kg x m / Amp x
Answer:
The dimensional formula for electric field is
Explanation:
Force on a point charge is given by Coulomb’s Law. Coulomb’s Law gives magnitude of force(F) between two point charges q1 and q2 separate by distance r.
Where,
Here, Unit of force = Newton & unit of
Electric field (E) is field produced by a charge Q around its surroundings.
Say a point test charge q is placed at distance r from Q. Then --- (2)
From (1) & (2), we can observe that,
E = F/q = m x a / I x t
= Newton / Coulomb = Kg x m / Amp x
Hence dimensional formula for electric field is
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